Holiday shopping has become a bit of spectacle, hasn't it? Between the rise of Black Friday sales and the mass hysteria that can ensue over "it-gifts", it's not hard to see how you could get a sort of disturbing, secret enjoyment about watching the world's mad dash to buy the right presents. For some of us, though, watching simply won't be enough... Which is why a couple of UK-based online bookies are setting odds for what video game will sell the most copies this holiday season. Of course, the odds heavily favor Call of Duty: Black Ops II. With Call of Duty games winning the holiday race for the last three years, how could they not?
As anyone familiar with the Milton Bradley game Battleship (soon to be a major motion picture) knows, you try to sink your opponent's fleet by targeting map coordinates on a 10x10 grid to attack. If a part of his or her ship occupies that coordinate, it register a 'hit,' and if you hit every coordinate covered by a ship (each ship occupies from two to five squares), that ship sinks. What makes this tricky, of course, is that you don't know where any of their ships are at the start of the game, although you can make some inferences, since every ship occupies a straight line. What are the odds of winning a game of Battleship outright by scoring hit after hit without ever missing? Book of Odds has crunched the numbers and concluded that they are 1 in 597,383,937.